document.write( "Question 717612: A can do a piece of work in 2 days as B can do in 3 days. B can do as much work in 4 days as C can do in 5 days. If A,B& C finish the work together in 10 days. In how many days B can finish the work alone ? \n" ); document.write( "
Algebra.Com's Answer #440484 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A can do a piece of work in 2 days as B can do in 3 days. \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "3A = 2B \n" ); document.write( "A = \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( " B can do as much work in 4 days as C can do in 5 days. \n" ); document.write( " \n" ); document.write( "4C = 5B \n" ); document.write( "C = \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( " If A, B & C finish the work together in 10 days. \n" ); document.write( "Let the completed job = 1 \n" ); document.write( " \n" ); document.write( "Replace A and C \n" ); document.write( " \n" ); document.write( "Multiply by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "multiply by 12 \n" ); document.write( "3(50) + 100 + 4(20) = 10B \n" ); document.write( "150 + 100 + 80 \n" ); document.write( "330 = 10B \n" ); document.write( "B = 330/10 \n" ); document.write( "B = 33 days B can finish the work alone? \n" ); document.write( " |