document.write( "Question 63270: Given the point (-2, -1 and a slope of 3/2 find the equation of the line having this slope and point\r
\n" ); document.write( "\n" ); document.write( "This is confusing me!!!!!!!!!\r
\n" ); document.write( "\n" ); document.write( "lackinmath \n" ); document.write( "
Algebra.Com's Answer #44041 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
First, you must be convinced that knowing
\n" ); document.write( "1) a point
\n" ); document.write( "2) the slope
\n" ); document.write( "of a line determines that line, and therefore
\n" ); document.write( "the equation of the line.
\n" ); document.write( "First imagine the x-y co-ordinates
\n" ); document.write( "Then imagine the x-y plane FILLED with lines of a certain
\n" ); document.write( "slope, say 3/2.
\n" ); document.write( "Now convince yourself that saying \"I only want the line
\n" ); document.write( "that goes through the point (-2,-1) eliminates all other lines but one.
\n" ); document.write( "Convinced? OK
\n" ); document.write( "point-slope formula is
\n" ); document.write( "\"%28y+-+y%5B1%5D%29+%2F%28+x+-+x%5B1%5D%29+=+m%29\"
\n" ); document.write( "where m = slope
\n" ); document.write( "and (x[1], y[1]) = (-2,-1)
\n" ); document.write( "\"%28y+-+%28-1%29%29+%2F+%28x+-+%28-2%29%29+=+3%2F2\"
\n" ); document.write( "\"%28y+%2B+1%29+%2F+%28x+%2B+2%29+=+3%2F2\"
\n" ); document.write( "multiply both sides by 2
\n" ); document.write( "\"%282y+%2B+2%29+%2F+%28x+%2B+2%29+=+3\"
\n" ); document.write( "multiply both sides by x+2
\n" ); document.write( "\"2y+%2B+2+=+3x+%2B+6\"
\n" ); document.write( "\"2y+=+3x+%2B+4\"
\n" ); document.write( "\"y+=+%283%2F2%29x+%2B+2\"
\n" ); document.write( "now check it
\n" ); document.write( "It does have slope = 3/2, since it's in the form
\n" ); document.write( "y = mx + b
\n" ); document.write( "Does it go through (-2,-1)?
\n" ); document.write( "\"-1+=+%283%2F2%29%2A%28-2%29+%2B+2\"
\n" ); document.write( "\"-1+=+-3+%2B+2\"
\n" ); document.write( "\"-1+=+-1\"
\n" ); document.write( "OK\r
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