document.write( "Question 63271This question is from textbook
\n" ); document.write( ": I am having trouble on this homework problem. Any help would be appreciated. Thank you. \r
\n" ); document.write( "\n" ); document.write( "If a6=-17 and S6=-12 find a1 and d \n" ); document.write( "
Algebra.Com's Answer #44039 by uma(370)\"\" \"About 
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Given the 6th term is - 17 and the sum upto 6 terms is -12\r
\n" ); document.write( "\n" ); document.write( "Let the first term be a1 and the common difference be d
\n" ); document.write( "Then 6th term = a1 + (6-1) * d
\n" ); document.write( " = a1 + 5d\r
\n" ); document.write( "\n" ); document.write( "Thus a1 + 5d = - 17 -------------------(1)\r
\n" ); document.write( "\n" ); document.write( "Sum upto 6 terms = (6/2)*(a1+a6)
\n" ); document.write( " = 3*(a1 + -17)
\n" ); document.write( " = 3(a1 - 17)\r
\n" ); document.write( "\n" ); document.write( "==> 3(a1-17) = - 12
\n" ); document.write( "==> 3a1 - 51 = -12
\n" ); document.write( "==> 3a1 - 51 + 51 = - 12 + 51
\n" ); document.write( "==> 3a1 = 39
\n" ); document.write( "==> 3a1/3 = 39/3
\n" ); document.write( "==> a1 = 13
\n" ); document.write( "Plugging in a1 = 13 in (1) we get,
\n" ); document.write( "13 + 5d = -17
\n" ); document.write( "==> 13 + 5d - 13 = - 17 - 13
\n" ); document.write( "==> 5d = - 30
\n" ); document.write( "==> 5d/5 = -30/5
\n" ); document.write( "==> d = -6\r
\n" ); document.write( "\n" ); document.write( "Thus a1 = 13 and d = -6\r
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\n" ); document.write( "\n" ); document.write( "Good Luck!!!
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