document.write( "Question 63260This question is from textbook
\n" ); document.write( ": The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #44035 by uma(370) $\"\"$ $\"About$

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Let the width of the rectangle be x in.
\n" ); document.write( "So length = (2x + 2) in\r
\n" ); document.write( "\n" ); document.write( "Then perimeter = 2*(l + w)
\n" ); document.write( " = 2*(2x + 2 + x)
\n" ); document.write( " = 2*(3x + 2)
\n" ); document.write( " = 6x + 4\r
\n" ); document.write( "\n" ); document.write( "Given perimeter = 34\r
\n" ); document.write( "\n" ); document.write( "==> 6x + 4 = 34
\n" ); document.write( "==> 6x + 4 - 4 = 34 - 4
\n" ); document.write( "==> 6x = 30
\n" ); document.write( "==> 6X/6 = 30/6
\n" ); document.write( "==> X = 5\r
\n" ); document.write( "\n" ); document.write( "So the width of the rectangle = 5 in
\n" ); document.write( "length of the rectangle = 2x + 2
\n" ); document.write( " = 10 + 2
\n" ); document.write( " = 12 in\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Good Luck!!! \n" ); document.write( "

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