document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=717602>Question 717602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6.5log/5 3x=20  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440347 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <ul><li>\"6.5log/5 3x\" is an invalid expression.</li><li>Even if \"6.5log/5 3x\" made sense, what are you/we supposed to do with the equation??</li></ul><BR>\n" );
document.write( "Please re-post your question. Include the instructions that say what we are supposed to do. And, since logarithms are notoriously difficult to type on a keyboard, try to use some English to help describe the expression. For example:<BR>\n" );
document.write( "\"6.5 times the base 5 log of 3x\" might be what \"6.5log/5 3x\" was intended to mean. </SPAN>\n" );
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