document.write( "Question 63260This question is from textbook
\n" );
document.write( ": The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle. \n" );
document.write( "
Algebra.Com's Answer #44034 by jai_kos(139)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given the length = 2 inches more than the width\r \n" ); document.write( "\n" ); document.write( "If width = \"y\" \n" ); document.write( "Then the length = 2 + width = 2 + y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is given by...\r \n" ); document.write( "\n" ); document.write( "perimeter = 2 length + 2 *width\r \n" ); document.write( "\n" ); document.write( "perimeter = 2(2+y)+ 2y\r \n" ); document.write( "\n" ); document.write( "34 = 4 + 2y + 2y\r \n" ); document.write( "\n" ); document.write( "34 = 4 + 4y\r \n" ); document.write( "\n" ); document.write( "34 - 4 = 4y\r \n" ); document.write( "\n" ); document.write( "30 = 4y\r \n" ); document.write( "\n" ); document.write( "30 / 4 = y \r \n" ); document.write( "\n" ); document.write( "15 /2 = y\r \n" ); document.write( "\n" ); document.write( "7.5 = y\r \n" ); document.write( "\n" ); document.write( "The width = 7.5 inches\r \n" ); document.write( "\n" ); document.write( "Now the length = 2 + y = 2 + 7.5 = 9.5 inches\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |