document.write( "Question 686462: 10x + 3x – 63 = 2
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Algebra.Com's Answer #440324 by lenny460(1073) $\"\"$ $\"About$

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10x + 3x – 63 = 2
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\n" ); document.write( "\n" ); document.write( "10x + 3x - 63 = 2\r
\n" ); document.write( "\n" ); document.write( "Combine like terms:\r
\n" ); document.write( "\n" ); document.write( "10x + 3x = 13x\r
\n" ); document.write( "\n" ); document.write( "Therefore:\r
\n" ); document.write( "\n" ); document.write( "13x - 63 = 2\r
\n" ); document.write( "\n" ); document.write( "Add 63 to each side of the equation.\r
\n" ); document.write( "\n" ); document.write( "13x - 63 + 63 = 2 + 63\r
\n" ); document.write( "\n" ); document.write( "Combine like terms:\r
\n" ); document.write( "\n" ); document.write( "-63 + 63 = 0\r
\n" ); document.write( "\n" ); document.write( "2 + 63 = 65\r
\n" ); document.write( "\n" ); document.write( "13x = 65\r
\n" ); document.write( "\n" ); document.write( "Divide each side by 13\r
\n" ); document.write( "\n" ); document.write( "13x/13 = 65/13\r
\n" ); document.write( "\n" ); document.write( "x = 5\r
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