document.write( "Question 63261This question is from textbook
\n" ); document.write( ": A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100 lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture? \n" ); document.write( "
Algebra.Com's Answer #44032 by jai_kos(139)\"\" \"About 
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LEt the coffee merchant has x lb and y lb of the coffee beans\r
\n" ); document.write( "\n" ); document.write( "x + y =100\r
\n" ); document.write( "\n" ); document.write( "x* 9 +y * 12 = 11.25 * 100\r
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\n" ); document.write( "\n" ); document.write( "We shallsolve the given equations\r
\n" ); document.write( "\n" ); document.write( "WE rewrite the equation(1) as\r
\n" ); document.write( "\n" ); document.write( "x = 100 - y -->(3)\r
\n" ); document.write( "\n" ); document.write( "Now substitue equation(3) in equation(2), we get\r
\n" ); document.write( "\n" ); document.write( "(100 - y) * 9 + y *12 = 11.25 * 100\r
\n" ); document.write( "\n" ); document.write( "900 - 9y + 12y = 1125\r
\n" ); document.write( "\n" ); document.write( "900 + 3y = 1125\r
\n" ); document.write( "\n" ); document.write( "3y = 1125 - 900 = 225\r
\n" ); document.write( "\n" ); document.write( "3y =225\r
\n" ); document.write( "\n" ); document.write( "Divide by 3 we get,\r
\n" ); document.write( "\n" ); document.write( "y = 225 / 3\r
\n" ); document.write( "\n" ); document.write( "y = 75 lb\r
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\n" ); document.write( "\n" ); document.write( "Now substitue the \"y\" value in equation)3), we get\r
\n" ); document.write( "\n" ); document.write( "x = 100 - 75 = 25lb\r
\n" ); document.write( "\n" ); document.write( "Therefore the quantity of coffee beans of first type is 75lb and the second type is 25 lb
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