document.write( "Question 63265: i dont know where this question should be posted Q. A certain isotope has a decay rate of-1.5% find its half life
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document.write( "thank you \n" );
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Algebra.Com's Answer #44031 by uma(370) ![]() You can put this solution on YOUR website! Given that the decay rate = 1.5%\r \n" ); document.write( "\n" ); document.write( "So half life = ln(2)/0.015\r \n" ); document.write( "\n" ); document.write( " = 0.6932/0.015\r \n" ); document.write( "\n" ); document.write( " = 46.2\r \n" ); document.write( "\n" ); document.write( "Thus the isotope has a half life of 46.2 yrs \n" ); document.write( "which means that the isotope would reduce to half its initial value in 46.2 yrs with the decay rate being 1.5%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Good Luck!!! \n" ); document.write( " |