document.write( "Question 717432: Two ships leave San Francisco at the same time. One travels N 40 W at a speed of 20 knots. The other travels S 10 W at a speed of 15 knots. How far apart are they after 11 hours? ( 1 knot= 1 nautical mile per hour) \n" ); document.write( "
Algebra.Com's Answer #440306 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! The distance from starting point of the mostly northward ship is 20*t, and the distance from starting point of the mostly southward ship is 15*t. If my understanding of the directions are correct, the angle of the two distance sides is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A figure should be shown, but that is a long process here for me, yet I can feel a use for Law of Cosines. Using D for how far apart at 11 hours, the other side of the triangle, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |