document.write( "Question 717432: Two ships leave San Francisco at the same time. One travels N 40 W at a speed of 20 knots. The other travels S 10 W at a speed of 15 knots. How far apart are they after 11 hours? ( 1 knot= 1 nautical mile per hour) \n" ); document.write( "
Algebra.Com's Answer #440306 by josgarithmetic(39618)\"\" \"About 
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The distance from starting point of the mostly northward ship is 20*t, and the distance from starting point of the mostly southward ship is 15*t. If my understanding of the directions are correct, the angle of the two distance sides is \"50%2B80\" degrees. N 40 W may be 50 degrees northward from West and S 10 W may be 80 degrees southward from West. So I guess, the angle at starting point is \"50%2B80=130\" degrees.\r
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\n" ); document.write( "\n" ); document.write( "A figure should be shown, but that is a long process here for me, yet I can feel a use for Law of Cosines. Using D for how far apart at 11 hours, the other side of the triangle, \"D%5E2=%2820t%29%5E2%2B%2815t%29%5E2-2%2820t%29%2815t%29cos%28130%29\", and we want to finally let \"t=11\".\r
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\n" ); document.write( "\n" ); document.write( "\"D%5E2=400t%5E2%2B225t%5E2-600t%5E2%2Acos%28130%29\"
\n" ); document.write( "\"D%5E2=625t%5E2-600t%5E2%2Acos%28130%29\"
\n" ); document.write( "\"D%5E2=25t%5E2%2825-24%2Acos%28130%29%29\"
\n" ); document.write( "\"D%5E2=%2825t%5E2%29%2840.4269%29\"
\n" ); document.write( "\"D=5t%2Asqrt%2840.4269%29\"
\n" ); document.write( "\"highlight%28D=5%2At%2A%286.358%29%29\", and LET \"t=11\".
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