document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63261>Question 63261</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100 lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture? </SPAN>\n" );
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document.write( "Let x lb of the first type be mixed with y lb of the second type.<BR>\n" );
document.write( "Then x + y = 100 --------------------(1)\r<BR>\n" );
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document.write( "Cost of x lb at $9 per lb = $ 9x<BR>\n" );
document.write( "Cost of y lb at $ 12 per lb = $12y<BR>\n" );
document.write( "Cost of 100 pb of the mixture = 100 * 11.25 = 1125\r<BR>\n" );
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document.write( "==> 9x + 12y = 1125 ------------------(2)<BR>\n" );
document.write( "    9x + 9y = 900 -----------------(1) x 9\r<BR>\n" );
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document.write( "Subtracting the above two equations we get...\r<BR>\n" );
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document.write( "     3y = 225<BR>\n" );
document.write( "==> 3y/3 = 225/3<BR>\n" );
document.write( "==> y = 75\r<BR>\n" );
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document.write( "PLugging in y = 75 in (1) we get.. x = 25\r<BR>\n" );
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document.write( "Thus he has to mix 25 lb of $9 type with 75 lb of $ 12 type to get the required mixture.\r<BR>\n" );
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document.write( "Good Luck!!! <BR>\n" );
document.write( " </SPAN>\n" );
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