document.write( "Question 717301: What is the extraneous solution of sqrt(x-3)= (x-5)
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document.write( "also sqrt of(x+4)=sqrt(3x) \n" );
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Algebra.Com's Answer #440232 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! First we find solutions. Then we determine which, if any, are extraneous. \n" ); document.write( " \n" ); document.write( "Square both sides: \n" ); document.write( " \n" ); document.write( "Squaring the left side is as easy as it looks. Squaring an expression like the right side is where a lot of mistakes are made. It is \n" ); document.write( " \n" ); document.write( "which simplifies to: \n" ); document.write( " \n" ); document.write( "Now that x is out of the square root we can solve for it. This is a quadratic equation so we want one side to be zero. Subtracting x and adding 3 we get: \n" ); document.write( " \n" ); document.write( "Next we factor (or use the Quadratic Formula). This factors fairly easily: \n" ); document.write( " \n" ); document.write( "From the Zero Product Property: \n" ); document.write( "x-7 = 0 or x-4 = 0 \n" ); document.write( "Solving these we get: \n" ); document.write( "x = 7 or x = 4 \n" ); document.write( "Now we check. Use the original equation: \n" ); document.write( " \n" ); document.write( "Checking x = 7: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Checking x = 4: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So x = 7 is actually a solution and x = 4 is extraneous. \n" ); document.write( " \n" ); document.write( "Square both sides: \n" ); document.write( " \n" ); document.write( "x+4 = 3x \n" ); document.write( "Subtract x: \n" ); document.write( "4 = 2x \n" ); document.write( "Divide by 2: \n" ); document.write( "2 = x \n" ); document.write( "Check. \n" ); document.write( " \n" ); document.write( "Checking x = 2: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x = 2 is the solution to this equation. There are no extraneous solutions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |