document.write( "Question 717301: What is the extraneous solution of sqrt(x-3)= (x-5)
\n" ); document.write( "also sqrt of(x+4)=sqrt(3x)
\n" ); document.write( "

Algebra.Com's Answer #440232 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
First we find solutions. Then we determine which, if any, are extraneous.

\n" ); document.write( "\"sqrt%28x-3%29=+%28x-5%29\"
\n" ); document.write( "Square both sides:
\n" ); document.write( "\"%28sqrt%28x-3%29%29%5E2=+%28x-5%29%5E2\"
\n" ); document.write( "Squaring the left side is as easy as it looks. Squaring an expression like the right side is where a lot of mistakes are made. It is not \"x%5E2-5%5E2\"!! To square a two-term expression like (x-5) correctly we must use FOIL on (x-5)(x-5) or use the \"%28a-b%29%5E2+=+a%5E2-2ab%2Bb%5E2\" pattern. I prefer using the pattern:
\n" ); document.write( "\"x-3=+%28x%29%5E2-2%28x%29%285%29%2B5%5E2\"
\n" ); document.write( "which simplifies to:
\n" ); document.write( "\"x-3=+x%5E2-10x%2B25\"
\n" ); document.write( "Now that x is out of the square root we can solve for it. This is a quadratic equation so we want one side to be zero. Subtracting x and adding 3 we get:
\n" ); document.write( "\"0+=+x%5E2-11x%2B28\"
\n" ); document.write( "Next we factor (or use the Quadratic Formula). This factors fairly easily:
\n" ); document.write( "\"0+=+%28x-7%29%28x-4%29\"
\n" ); document.write( "From the Zero Product Property:
\n" ); document.write( "x-7 = 0 or x-4 = 0
\n" ); document.write( "Solving these we get:
\n" ); document.write( "x = 7 or x = 4

\n" ); document.write( "Now we check. Use the original equation:
\n" ); document.write( "\"sqrt%28x-3%29=+%28x-5%29\"
\n" ); document.write( "Checking x = 7:
\n" ); document.write( "\"sqrt%287-3%29=+%287-5%29\"
\n" ); document.write( "\"sqrt%284%29=+%282%29\"
\n" ); document.write( "\"2+=+%282%29\" Check!
\n" ); document.write( "Checking x = 4:
\n" ); document.write( "\"sqrt%284-3%29=+%284-5%29\"
\n" ); document.write( "\"sqrt%281%29+=+%28-1%29\"
\n" ); document.write( "\"1+=+%28-1%29\" Check fails!
\n" ); document.write( "So x = 7 is actually a solution and x = 4 is extraneous.

\n" ); document.write( "\"sqrt%28x%2B4%29=sqrt%283x%29\"
\n" ); document.write( "Square both sides:
\n" ); document.write( "\"%28sqrt%28x%2B4%29%29%5E2=%28sqrt%283x%29%29%5E2\"
\n" ); document.write( "x+4 = 3x
\n" ); document.write( "Subtract x:
\n" ); document.write( "4 = 2x
\n" ); document.write( "Divide by 2:
\n" ); document.write( "2 = x
\n" ); document.write( "Check.
\n" ); document.write( "\"sqrt%28x%2B4%29=sqrt%283x%29\"
\n" ); document.write( "Checking x = 2:
\n" ); document.write( "\"sqrt%282%2B4%29=sqrt%283%282%29%29\"
\n" ); document.write( "\"sqrt%286%29=sqrt%286%29\" Check!
\n" ); document.write( "x = 2 is the solution to this equation. There are no extraneous solutions.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );