document.write( "Question 715930: How do you find the focus of y=1/20(x+5)^2-6 \n" ); document.write( "

Algebra.Com's Answer #440225 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
How do you find the focus of y=1/20(x+5)^2-6
\n" ); document.write( "***
\n" ); document.write( "Basic form of equation for a parabola that opens upward: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex
\n" ); document.write( "y=1/20(x+5)^2-6
\n" ); document.write( "(y+6)=(1/20)(x+5)^2
\n" ); document.write( "(x+5)^2=20(y+6)
\n" ); document.write( "vertex: (-5,-6)
\n" ); document.write( "axis of symmetry: y=-5
\n" ); document.write( "4p=20
\n" ); document.write( "p=5
\n" ); document.write( "focus: (-5,-1) (p-distance above vertex on the axis of symmetry)
\n" ); document.write( " \n" ); document.write( "

\n" );