document.write( "Question 717310: The length of a rectangle is 10 ft longer than twice the width. If the perimeter is 74 ft, find the length and width of a rectangle. \n" ); document.write( "
Algebra.Com's Answer #440200 by mathworm7271(5)\"\" \"About 
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x=width
\n" ); document.write( "2x+10=length\r
\n" ); document.write( "\n" ); document.write( "Perimeter=2x+2(2x+10)
\n" ); document.write( "2x+4x+20
\n" ); document.write( "6x+20
\n" ); document.write( "Perimeter=74
\n" ); document.write( "Plug them in...
\n" ); document.write( "74=6x+20
\n" ); document.write( "Subtract 20 on both sides
\n" ); document.write( "54=6x
\n" ); document.write( "Divide both sides by 6
\n" ); document.write( "9=x
\n" ); document.write( "2(9)+10
\n" ); document.write( "18+10
\n" ); document.write( "28=length
\n" ); document.write( "9=width
\n" ); document.write( "
\n" );