document.write( "Question 717310: The length of a rectangle is 10 ft longer than twice the width. If the perimeter is 74 ft, find the length and width of a rectangle. \n" ); document.write( "
Algebra.Com's Answer #440200 by mathworm7271(5)![]() ![]() You can put this solution on YOUR website! x=width \n" ); document.write( "2x+10=length\r \n" ); document.write( "\n" ); document.write( "Perimeter=2x+2(2x+10) \n" ); document.write( "2x+4x+20 \n" ); document.write( "6x+20 \n" ); document.write( "Perimeter=74 \n" ); document.write( "Plug them in... \n" ); document.write( "74=6x+20 \n" ); document.write( "Subtract 20 on both sides \n" ); document.write( "54=6x \n" ); document.write( "Divide both sides by 6 \n" ); document.write( "9=x \n" ); document.write( "2(9)+10 \n" ); document.write( "18+10 \n" ); document.write( "28=length \n" ); document.write( "9=width \n" ); document.write( " |