document.write( "Question 717216: here is the what the question asks.
\n" ); document.write( "Find the slope of the line perpendicular to the following line,
\n" ); document.write( "now it shows a graph with a line going through the middle and the top point says (-2,1) and the lower point says (2,-1). please help thanks
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Algebra.Com's Answer #440154 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "the slope of the lines are negative reciprocals to each other\r
\n" ); document.write( "\n" ); document.write( "if \"m\" is the slope of the line, the line perpendicular to the that line will have the slope \"m%5Bp%5D=-1%2Fm\"\r
\n" ); document.write( "\n" ); document.write( "you first need to find the equation of the line going through the (-2,1) and (2,-1) and find its slope\r
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Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-2, 1) and (x2, y2) = (2, -1).
\n" ); document.write( " Slope a is \"a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-1-1%29%2F%282--2%29+=+-0.5\".
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"-0.5%2A-2+%2Bb+=+0\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=1--0.5%2A-2+=+0\".
\n" ); document.write( "
\n" ); document.write( " y=(-0.5)x + (0)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "so, the slope \"m=-0.5=-1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "then the line perpendicular to the that line will have the slope \"m%5Bp%5D=-1%2F%28-1%2F2%29=2\"\r
\n" ); document.write( "\n" ); document.write( "that line could be \"y=2x\"\r
\n" ); document.write( "\n" ); document.write( "see them on a graph:\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C-0.5x%2C+2x%29+\" \r
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