document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=717124>Question 717124</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following system of linear equation addition method\r<BR>\n" );
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document.write( "8x+3y=-5<BR>\n" );
document.write( "3x+3y=10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440146 by </B><A HREF=/tutors/aboutme.mpl?userid=20800563><B>20800563(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=20800563><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+3y=10 let multiply this equation with -1 and then obtain that -3x-3y=-10 then let add this one:\r<BR>\n" );
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document.write( "       8x+3y=-5<BR>\n" );
document.write( "      -3x-3y=-10<BR>\n" );
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document.write( "     5x=-15 and x=-3 so when we put x for 8x+3y=-5 we have -24+3y=-5 and then we have 3y=19 so y=19/3 and we get solution (-3,19/3) </SPAN>\n" );
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