document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=717102>Question 717102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The probability that a particular machine breaks down on any day is 0.2 and is independent of the breakdowns on any other day. The machine can break down only once per day. Calculate the probability that the machine breaks down two or more times in ten days.<BR>\n" );
document.write( "(A) 0.0175 (B) 0.0400 (C) 0.2684 (D) 0.6242 (E) 0.9596 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440120 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440120\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a binomial probability problem. The probability of a \"success\" is p = 0.2 since we want to determine the likelihodd of breakdown.  <BR>\n" );
document.write( "The general formula for the probability of m successes in n trials is:<BR>\n" );
document.write( "P(m) = combin(n,m)*p^m*(1-p)^(n-m)<BR>\n" );
document.write( "In this case there are 10 trials, so n = 10<BR>\n" );
document.write( "P(2 or more) = 1 - P(less than 2)<BR>\n" );
document.write( "P(0) = 0.107374<BR>\n" );
document.write( "P(1) = 0.268435<BR>\n" );
document.write( "So P(2 or more) = 1 - .1074 - 0.2684 = 0.6242 (D) </SPAN>\n" );
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