document.write( "Question 717066: Please answer this equation: 4 + 3 |5 - x| = 154 \n" ); document.write( "

Algebra.Com's Answer #440101 by jsmallt9(3758) $\"\"$ $\"About$

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$\"4+%2B+3%2Aabs%285+-+x%29+=+154\"$
\n" ); document.write( "First, isolate the absolute value. Subtracting 4:
\n" ); document.write( " $\"3%2Aabs%285+-+x%29+=+150\"$
\n" ); document.write( "and divide by 3:
\n" ); document.write( " $\"abs%285+-+x%29+=+50\"$

\n" ); document.write( "With the absolute value isolated, we now rewrite the equation as two equivalent equations without absolute value. If the absolute value of something is 50 then it must be either a 50 or a -50:
\n" ); document.write( " $\"5-x+=+50\"$ or $\"5-x+=+-50\"$
\n" ); document.write( "With the x out of the absolute value, we can now solve for it. Subtracting 5 in each equation:
\n" ); document.write( " $\"-x+=+45\"$ or $\"-x+=+-55\"$
\n" ); document.write( "Dividing (or multiplying) by -1:
\n" ); document.write( " $\"x+=+-45\"$ or $\"x+=+55\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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