document.write( "Question 717075: how can I solve this use the eccentricity of each hyperbola to find its equation in standard form center(4,1),horizontal transverse axis is 12 and eccentricity 4/3 \n" ); document.write( "
Algebra.Com's Answer #440075 by KMST(5328)![]() ![]() You can put this solution on YOUR website! The equation of a hyperbola with a horizontal transverse axis can be written in the form \n" ); document.write( " \n" ); document.write( "I had to look it up (not good with names), but that is what is called the standard form. \n" ); document.write( "(h,k) is the center \n" ); document.write( "Center, vertices, and foci are on the horizontal line \n" ); document.write( "For the vertices, \n" ); document.write( " \n" ); document.write( "They are at distance \n" ); document.write( "and \n" ); document.write( "The segment (and the distance) between the vertices is called the transverse axis. \n" ); document.write( " \n" ); document.write( "So far we know \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The eccentricity \n" ); document.write( "(distance from each focus to the center) as \n" ); document.write( " \n" ); document.write( "and it turns out that \n" ); document.write( "We know \n" ); document.write( " \n" ); document.write( "Then, plugging that (along with \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Finally, plugging the values given (or very easily found) for \n" ); document.write( " |