document.write( "Question 716905: Simplify.\r
\n" ); document.write( "\n" ); document.write( "((x^-2) / (2y^-1)^2
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Algebra.Com's Answer #440069 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E%28-2%29+%2F+%282%28y%5E%28-1%29%29%5E2%29\"
\n" ); document.write( "Of course must follow the order of operations (aka PEMDAS or GEMDAS). So we start with the power of a power in the denominator. The rule here is to multiply the exponents:
\n" ); document.write( "\"x%5E%28-2%29+%2F+%282y%5E%28-2%29%29\"
\n" ); document.write( "This is a simplified expression... unless you consider negative exponents \"unsimplified\". If this is so then we can eliminate the negative exponents quickly or slowly.

\n" ); document.write( "Quickly.
\n" ); document.write( "The fast way is to understand that negative exponents mean reciprocals. A negative exponent on a factor in the numerator becomes that factor with a positive exponent in the denominator and vice versa. Using this
\n" ); document.write( "\"x%5E%28-2%29+%2F+%282y%5E%28-2%29%29\"
\n" ); document.write( "becomes:
\n" ); document.write( "\"y%5E2+%2F+%282x%5E2%29\"
\n" ); document.write( "This is the simplified expression with positive exponents. (Note: Exponents only apply to whatever is immediately in front of it! So the exponent of -2 in the denominator applies only to the y, not to the 2! This is why the 2 stays in the denominator.)

\n" ); document.write( "Slowly.
\n" ); document.write( "The methodical way is to use the rule:
\n" ); document.write( "\"a%5E%28-n%29+=+1%2Fa%5En\"
\n" ); document.write( "Using this rule on the two negative exponents in:
\n" ); document.write( "\"x%5E%28-2%29+%2F+%282y%5E%28-2%29%29\"
\n" ); document.write( "we get:
\n" ); document.write( "\"%281%2Fx%5E2%29%2F%282%281%2Fy%5E2%29%29%29\"
\n" ); document.write( "Simplifying...
\n" ); document.write( "\"%281%2Fx%5E2%29%2F%282%2Fy%5E2%29%29\"
\n" ); document.write( "Multiplying the numerator and denominator of the \"big\" fraction by the lowest common denominator of the \"little\" fractions, \"x%5E2y%5E2\", will eliminate the \"little\" fractions:
\n" ); document.write( "\"%28%281%2Fx%5E2%29%2F%282%2Fy%5E2%29%29%2A%28%28x%5E2y%5E2%29%2F%28x%5E2y%5E2%29%29\"
\n" ); document.write( "giving us:
\n" ); document.write( "\"y%5E2+%2F+%282x%5E2%29\"
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