document.write( "Question 717042: Solve for x: Log4/x(x is the base)= 5/4 + Logx/4(4 is the base). Text book answer: x = 0,334,text book author confirms value of x. Please assist. \n" ); document.write( "
Algebra.Com's Answer #440066 by jsmallt9(3759)\"\" \"About 
You can put this solution on YOUR website!
\"log%28x%2C+%284%29%29+=+5%2F4+%2B+log%284%2C+%28x%29%29\"
\n" ); document.write( "In order to solve this we need to have the bases of the logarithms match. For this we will use the change of base formula, \"log%28a%2C+%28p%29%29+=+log%28b%2C+%28p%29%29%2Flog%28b%2C+%28a%29%29\". We can either change the first log from base x to base 4, the second log from base x to base 4 or change both logs to base whatever-base-we-want. I'm going to change the first log:
\n" ); document.write( "\"log%284%2C+%284%29%29%2Flog%284%2C+%28x%29%29+=+5%2F4+%2B+log%284%2C+%28x%29%29\"
\n" ); document.write( "The numerator will simplify. When the base and the argument match like this, the log is 1:
\n" ); document.write( "\"1%2Flog%284%2C+%28x%29%29+=+5%2F4+%2B+log%284%2C+%28x%29%29\"

\n" ); document.write( "Now that the bases of the logs match we can start solving. Let's eliminate the fractions first. Multiplying by \"4log%284%2C+%28x%29%29\":
\n" ); document.write( "
\n" ); document.write( "Using the Distributive Property on the right side:
\n" ); document.write( "
\n" ); document.write( "Simplifying...
\n" ); document.write( "\"4+=5log%284%2C+%28x%29%29+%2B+4%28log%284%2C+%28x%29%29%29%5E2\"

\n" ); document.write( "The equation is in what is called \"quadratic form\". If you have trouble recognizing this, then a temporary variable can help:
\n" ); document.write( "Let \"q+=+log%284%2C+%28x%29%29\". Substituting this into our equation we get:
\n" ); document.write( "\"4+=+5q+%2B+4q%5E2\"
\n" ); document.write( "This is obviously a quadratic equation. We can solve this. Subtracting 4 (and reordering the terms):
\n" ); document.write( "\"0+=+4q%5E2+%2B+5q++-4\"
\n" ); document.write( "This will not factor so we must use the Quadratic formula:
\n" ); document.write( "\"q+=+%28-%285%29+%2B-+sqrt%28%285%29%5E2-4%284%29%28-4%29%29%29%2F2%284%29\"
\n" ); document.write( "Simplifying...
\n" ); document.write( "\"q+=+%28-%285%29+%2B-+sqrt%2825-4%284%29%28-4%29%29%29%2F2%284%29\"
\n" ); document.write( "\"q+=+%28-%285%29+%2B-+sqrt%2825%2B64%29%29%2F2%284%29\"
\n" ); document.write( "\"q+=+%28-%285%29+%2B-+sqrt%2889%29%29%2F2%284%29\"
\n" ); document.write( "\"q+=+%28-5+%2B-+sqrt%2889%29%29%2F8\"
\n" ); document.write( "which is short for:
\n" ); document.write( "\"q+=+%28-5+%2B+sqrt%2889%29%29%2F8\" or \"q+=+%28-5+-+sqrt%2889%29%29%2F8\"

\n" ); document.write( "Of course we are not interested in solutions for q. We want solutions for x. So now we substitute back in for the q:
\n" ); document.write( "\"log%284%2C+%28x%29%29+=+%28-5+%2B+sqrt%2889%29%29%2F8\" or \"log%284%2C+%28x%29%29+=+%28-5+-+sqrt%2889%29%29%2F8\"
\n" ); document.write( "Now we solve for x. The next step is to rewrite these equations in exponential form. Before that, however, let's get decimal approximations for the right sides. Rounded to 3 places we get:
\n" ); document.write( "\"log%284%2C+%28x%29%29+=+0.554\" or \"log%284%2C+%28x%29%29+=+-1.804\"

\n" ); document.write( "Now to exponential form... In general \"log%28a%2C+%28p%29%29+=+n\" is equivalent to \"p+=+a%5En\". Using this pattern on our equations we get:
\n" ); document.write( "\"x+=+4%5E0.554\" or \"x+=+4%5E%28-1.804%29\"
\n" ); document.write( "Using our calculators to find these powers of 4:
\n" ); document.write( "\"x+=+2.155\" or \"x+=+0.082\"

\n" ); document.write( "Next we check out solutions. This is not optional when solving logarithmic equations like this. You must at least ensure that all bases and all arguments are valid. (Valid bases and arguments are positive and bases cannot be a 1.) We can quickly see that both solutions will make the the bases and arguments of the logs valid. If we had gotten an invalid base or argument, then we would reject that solution.

\n" ); document.write( "If you want to complete the check to see if the solutions actually work (this part of the check is optional), then we would need to have logs with bases our calculators \"know\", base 10 (\"log\") or base e (\"ln\"). Using the change of base formula on the original equation:
\n" ); document.write( "\"log%28x%2C+%284%29%29+=+5%2F4+%2B+log%284%2C+%28x%29%29\"
\n" ); document.write( "to convert the logs to base e logs we get:
\n" ); document.write( "\"ln%284%29%2Fln%28x%29+=+5%2F4+%2B+ln%28x%29%2Fln%284%29\"
\n" ); document.write( "Then for each solution we replace the x's with that solution and use our calculators to see if it checks. (Note: Because our calculators give us decimal approximations, we may end up with a left side that is very, very close but not exactly equal to the right side. If so then we can assume that the solution checks. Both of these answers check.

\n" ); document.write( "We have two correct answers but you say that there is just one answer (which is different from both of the ones we found above). I can only suspect that the reason for this is that there is something wrong with the equation you posted. I hope that you can use the above to help you figure out the solution(s) to the actual equation.

\n" ); document.write( "P.S. One you have had some practice with quadratic form equations, you will no longer need a temporary variable. You will be able to see how to go directly from:
\n" ); document.write( "\"4+=5log%284%2C+%28x%29%29+%2B+4%28log%284%2C+%28x%29%29%29%5E2\"
\n" ); document.write( "to
\n" ); document.write( "\"0+=4%28log%284%2C+%28x%29%29%29%5E2+%2B+5log%284%2C+%28x%29%29+-+4+\"
\n" ); document.write( "to
\n" ); document.write( "
\n" ); document.write( "etc.
\n" ); document.write( "
\n" );