document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=716879>Question 716879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log 5x= log(2x+9) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440065 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The only way two logs of the same base can be equal is if their arguments are equal. So:<BR>\n" );
document.write( "5x = 2x + 9<BR>\n" );
document.write( "Now solve for x. </SPAN>\n" );
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