document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=716641>Question 716641</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Please help me solve this equation: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x2%2B48x%2By%2B158=0 ALIGN=MIDDLE  ALT=\"4x2%2B48x%2By%2B158=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a.Write the equation in standard form.<BR>\n" );
document.write( "b.Find the coordinates of the vertex and focus,direction of opening, the equations for the directrix and the axis of symmetry,and latus rectum<BR>\n" );
document.write( "c.Graph the equation of the parabola </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440063 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve this equation: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x2%2B48x%2By%2B158=0 ALIGN=MIDDLE  ALT=\"4x2%2B48x%2By%2B158=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a.Write the equation in standard form.<BR>\n" );
document.write( "4x2+48x+y+158=0<BR>\n" );
document.write( "y=-4x^2-48x-158<BR>\n" );
document.write( "..<BR>\n" );
document.write( "b.Find the coordinates of the vertex and focus,direction of opening, the equations for the directrix and the axis of symmetry,and latus rectum.<BR>\n" );
document.write( "complete the square:<BR>\n" );
document.write( "y=-4(x^2+12x+36)-158+144<BR>\n" );
document.write( "y=-4(x+6)^2-14  (vertex form of equation, y=-A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex.)<BR>\n" );
document.write( "(y+14)=-4(x+6)^2<BR>\n" );
document.write( "(x+6)^2=-(1/4)(y+14) (basic form of equation, (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex.)<BR>\n" );
document.write( "parabola opens downward<BR>\n" );
document.write( "vertex: (-6,-14)<BR>\n" );
document.write( "axis of symmetry: x=-6<BR>\n" );
document.write( "4p=1/4<BR>\n" );
document.write( "p=1/16<BR>\n" );
document.write( "focus: (-6,-(14+(1/16)) (p-distance below vertex on the axis of symmetry)<BR>\n" );
document.write( "directrix: y=((14+(1/16) (p-distance above vertex on the axis of symmetry)<BR>\n" );
document.write( "latus rectum=focal width=4p=1/4\r<BR>\n" );
document.write( "\n" );
document.write( "c.Graph the equation of the parabola<BR>\n" );
document.write( "see graph below:\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+300%2C+-10%2C+10%2C+-20%2C+10%2C-4x%5E2-48x-158%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-20%2C+10%2C-4x%5E2-48x-158%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );