document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=716658>Question 716658</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help find the vertex for the equation 4x+y^2+3y=-5<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440062 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the vertex for the equation <BR>\n" );
document.write( "4x+y^2+3y=-5<BR>\n" );
document.write( "complete the square:<BR>\n" );
document.write( "4x+(y^2+3y+9/4)=-5+9/4<BR>\n" );
document.write( "4x+(y+3/2)^2=-20/4+9/4=-11/4<BR>\n" );
document.write( "4x=-(y+3/2)^2-11/4<BR>\n" );
document.write( "x=-(1/4)(y+3/2)^2-11/16<BR>\n" );
document.write( "vertex form of equation for parabola that opens leftward: x=-A(y-k)^2+h, (h,k)=(x,y) coordinates of the vertex.<BR>\n" );
document.write( "For given problem:<BR>\n" );
document.write( "A=-(1/4)<BR>\n" );
document.write( "vertex:(-11/16,-3/2) </SPAN>\n" );
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