document.write( "Question 716902: The perimeter of a rectangle is twice the sum of its length and its width. The perimeter is 40 meters and its length is 2 meters more than twice its width. what is its length \n" ); document.write( "
Algebra.Com's Answer #440014 by jndarrell(58)![]() ![]() ![]() You can put this solution on YOUR website! Perimeter of rectangle= sum of all 4 sides or 2(L+W) \n" ); document.write( "Width: 'x' \n" ); document.write( "Length: 2x+2 \n" ); document.write( "Perimeter= 40\r \n" ); document.write( "\n" ); document.write( "2(x+2x+2)=40 \"OR\" \n" ); document.write( "x+x+2x+2+2x+2=40\r \n" ); document.write( "\n" ); document.write( "6x+4=40 \n" ); document.write( "Subtract 4 from both sides to get x term alone on one side \n" ); document.write( "6x=36 \n" ); document.write( "Divide both sides by 6 to get x alone \n" ); document.write( "x=6\r \n" ); document.write( "\n" ); document.write( "Length= 14m \n" ); document.write( " |