document.write( "Question 716617: In four years, Steve's age will be two years less than twice Anne's age. Three years ago, Steve was three times as old as Anne was then. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #439911 by stanbon(75887)\"\" \"About 
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In four years, Steve's age will be two years less than twice Anne's age. Three years ago, Steve was three times as old as Anne was then. How old is each now?
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\n" ); document.write( "Equations:
\n" ); document.write( "s+4 = 2a-2
\n" ); document.write( "s-3 = 3(a-3)
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\n" ); document.write( "Rearrange:
\n" ); document.write( "s = 2a-6
\n" ); document.write( "s = 3a-6
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\n" ); document.write( "That is a contradiction.
\n" ); document.write( "Ans: No solution
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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