document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=716359>Question 716359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a spherical bearing is to have a circumference of 7.2 cm with an error of no more than 0.1 cm. Set up an absolute value inequality and then determine the acceptable range of values for the diameter of the bearing.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439842 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = diameter of any random spherical bearing\r<BR>\n" );
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document.write( "If the circumference is 7.2, then the diameter is d = 7.2/pi = 2.2918\r<BR>\n" );
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document.write( "The absolute value inequality we'll use is\r<BR>\n" );
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document.write( "|x - t| <= e\r<BR>\n" );
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document.write( "where\r<BR>\n" );
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document.write( "t = target\r<BR>\n" );
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document.write( "e = error\r<BR>\n" );
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document.write( "So the target is roughly 2.2918 and the error is 0.1 (or less), so t = 2.2918 and e = 0.1\r<BR>\n" );
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document.write( "|x - t| <= e\r<BR>\n" );
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document.write( "|x - 2.2918| <= 0.1\r<BR>\n" );
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document.write( "-0.1 <= x - 2.2918 <= 0.1\r<BR>\n" );
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document.write( "-0.1 + 2.2918 <= x <= 0.1 + 2.2918\r<BR>\n" );
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document.write( "2.1918 <= x <= 2.3918\r<BR>\n" );
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document.write( "So the acceptable range of values for the diameter is between 2.1918 and 2.3918 (inclusive) </SPAN>\n" );
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