document.write( "Question 716220: The width of a rectangle is 3 feet more than twice the length. If the perimeter is 60 feet, find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #439789 by checkley79(3341)\"\" \"About 
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P=2L+2W
\n" ); document.write( "W=2L+3
\n" ); document.write( "60=2L+2(2L+3)
\n" ); document.write( "60=2L+4L+6
\n" ); document.write( "60-6=6L
\n" ); document.write( "54=6L
\n" ); document.write( "L=54/6
\n" ); document.write( "L=9 FEET IS THE LENGTH.
\n" ); document.write( "W=2*9+3
\n" ); document.write( "W=18+3
\n" ); document.write( "W=21 FEET FOR THE WIDTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "60=2*9+2*21
\n" ); document.write( "60=18=42
\n" ); document.write( "60=60
\n" ); document.write( "
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