document.write( "Question 716220: The width of a rectangle is 3 feet more than twice the length. If the perimeter is 60 feet, find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #439789 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "W=2L+3 \n" ); document.write( "60=2L+2(2L+3) \n" ); document.write( "60=2L+4L+6 \n" ); document.write( "60-6=6L \n" ); document.write( "54=6L \n" ); document.write( "L=54/6 \n" ); document.write( "L=9 FEET IS THE LENGTH. \n" ); document.write( "W=2*9+3 \n" ); document.write( "W=18+3 \n" ); document.write( "W=21 FEET FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "60=2*9+2*21 \n" ); document.write( "60=18=42 \n" ); document.write( "60=60 \n" ); document.write( " |