document.write( "Question 715927: The help desk for a software company logs the lengths of times of each call that technicians have with customers. Historical records based on the past 3 years indicate that call length (L) is a normally distributed variable with an average (μ) of 9.00 minutes and a standard deviation (σ) of 0.95 min. For each of the problems below, find the appropriate probability.
\n" ); document.write( "A) P(L ≤ 10.22) \r
\n" ); document.write( "\n" ); document.write( "B) P(L > 10.74) \r
\n" ); document.write( "\n" ); document.write( "C) P(7.67 ≤ L < 11.02) \r
\n" ); document.write( "\n" ); document.write( "D) The call times that enclose the central 81% of the distribution are:
\n" ); document.write( " Note: Round your answers to two decimal places for this problem.\r
\n" ); document.write( "\n" ); document.write( "I really need step by step help. Im not coming up with the correct answers..
\n" ); document.write( " Low: to High:
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Algebra.Com's Answer #439751 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
call length (L) is a normally distributed variable with an average (μ) of 9.00 minutes and a standard deviation (σ) of 0.95 min. For each of the problems below, find the appropriate probability.
\n" ); document.write( "A) P(L ≤ 10.22)
\n" ); document.write( "z(10.22) = (10.22-9)/0.95 = 1.2842
\n" ); document.write( "Ans: P(L<= 10.22) = P(z<=1.2842) = normalcdf(-100,1.2842) = 0.9005
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\n" ); document.write( "B) P(L > 10.74)
\n" ); document.write( "Find the z-value of 10.74.
\n" ); document.write( "Find the P(z is above that z-value)
\n" ); document.write( "Ans: 0.0335
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\n" ); document.write( "C) P(7.67 ≤ L < 11.02)
\n" ); document.write( "Find the z-value of those numbers.
\n" ); document.write( "Find the P(z is between those z-values)
\n" ); document.write( "Ans: 0.9025
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\n" ); document.write( "D) The call times that enclose the central 81% of the distribution are:
\n" ); document.write( "Note: Round your answers to two decimal places for this problem.
\n" ); document.write( "Draw the picture:
\n" ); document.write( "You have a left tail of 0.5000- 0.4150 = 0.085
\n" ); document.write( "invNorm(0.085) = -1.3722 for the left tail and +1.3722 for the right tail:
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\n" ); document.write( "Find the corresponding x-value using x = z*s+u
\n" ); document.write( "x = -1.3722*0.95+9 = 7.70
\n" ); document.write( "x = +1.3622*0.95+9 = 10.30
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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