document.write( "Question 716015: Please help me solve this word problem..
\n" ); document.write( "Khang and Hector live 22.8 miles apart. They decide to bicycle towards each other and meet somewhere in between. Hector's rate of speed is 90% of Khang's. They start out at the same time and meet 2 hours later. Find Hector's rate of speed. \n" ); document.write( "

Algebra.Com's Answer #439710 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
You can think of one of them standing still
\n" ); document.write( "and the other moving at the sum of their speeds
\n" ); document.write( "until they meet
\n" ); document.write( "Let $\"+k+\"$ = Khang's speed min mi/hr
\n" ); document.write( " $\"+.9k+\"$ = Hector's speed in mi/hr
\n" ); document.write( " $\"+22.8+=+%28+k+%2B+.9k+%29%2A2+\"$
\n" ); document.write( " $\"+1.9k+=+22.8+%2F+2+\"$
\n" ); document.write( " $\"+k+=+11.4+%2F+1.9+\"$
\n" ); document.write( " $\"+k+=+6+\"$ mi/hr
\n" ); document.write( " $\"+.9k+=+.9%2A6+\"$
\n" ); document.write( " $\"+.9k+=+5.4+\"$
\n" ); document.write( "Hector's speed is 5.4 km/hr
\n" ); document.write( "---------------------------
\n" ); document.write( "check answer:
\n" ); document.write( "Khang's equation:
\n" ); document.write( " $\"+d%5B1%5D+=+6%2A2+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+12+\"$ mi
\n" ); document.write( "Hector's equation:
\n" ); document.write( " $\"+d%5B2%5D+=+5.4%2A2+\"$
\n" ); document.write( " $\"+d%5B2%5D+=+10.8+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=+12+%2B+10.8+\"$
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=+22.8+\"$ mi
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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