document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=716056>Question 716056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I cannot figure out how to do the equation 1/2(2y+3)=-2/3(y-4) I get different answers every time, can you help me with what steps to take? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439700 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2(2y+3)=-2/3(y-4) <BR>\n" );
document.write( "(2y+3)2=-2(y-4)/3<BR>\n" );
document.write( "6y+9=-4y+16<BR>\n" );
document.write( "10y=7<BR>\n" );
document.write( "y=7/10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );