document.write( "Question 715940: Mark and sandy are participating in a bike a thon for charity. Mark over sleeps, so sandy gets a one hour head start and bikes at a speed of 12 miles per hour. To catch up to sandy, mark decides that he needs to bike at a speed of 15 miles per hour. Write and solve an equation to determine when mark will catch up to sandy. \n" ); document.write( "
Algebra.Com's Answer #439685 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Mark and sandy are participating in a bike a thon for charity. \n" ); document.write( " Mark over sleeps, so sandy gets a one hour head start and bikes at a speed of 12 miles per hour. \n" ); document.write( " To catch up to sandy, mark decides that he needs to bike at a speed of 15 miles per hour. \n" ); document.write( " Write and solve an equation to determine when mark will catch up to sandy. \n" ); document.write( ": \n" ); document.write( "Let t = time required by Mark to catch Sandy \n" ); document.write( "then \n" ); document.write( "(t+1) = Sandy's travel time \n" ); document.write( "; \n" ); document.write( "When M catches S, they will have traveled the same distance \n" ); document.write( "Write a distance equation; dist = speed * time \n" ); document.write( ": \n" ); document.write( "15t = 12(t+1) \n" ); document.write( "15t = 12t + 12 \n" ); document.write( "15t - 12t = 12 \n" ); document.write( "3t = 12 \n" ); document.write( "t = 12/3 \n" ); document.write( "t = 4 hrs for M to catch S \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this by finding the actual dist each traveled, should be the same. \n" ); document.write( "15(4) = 60 mi \n" ); document.write( "12(4+1) = 60 mi \n" ); document.write( " |