document.write( "Question 715940: Mark and sandy are participating in a bike a thon for charity. Mark over sleeps, so sandy gets a one hour head start and bikes at a speed of 12 miles per hour. To catch up to sandy, mark decides that he needs to bike at a speed of 15 miles per hour. Write and solve an equation to determine when mark will catch up to sandy. \n" ); document.write( "
Algebra.Com's Answer #439685 by ankor@dixie-net.com(22740)\"\" \"About 
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Mark and sandy are participating in a bike a thon for charity.
\n" ); document.write( " Mark over sleeps, so sandy gets a one hour head start and bikes at a speed of 12 miles per hour.
\n" ); document.write( " To catch up to sandy, mark decides that he needs to bike at a speed of 15 miles per hour.
\n" ); document.write( " Write and solve an equation to determine when mark will catch up to sandy.
\n" ); document.write( ":
\n" ); document.write( "Let t = time required by Mark to catch Sandy
\n" ); document.write( "then
\n" ); document.write( "(t+1) = Sandy's travel time
\n" ); document.write( ";
\n" ); document.write( "When M catches S, they will have traveled the same distance
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "15t = 12(t+1)
\n" ); document.write( "15t = 12t + 12
\n" ); document.write( "15t - 12t = 12
\n" ); document.write( "3t = 12
\n" ); document.write( "t = 12/3
\n" ); document.write( "t = 4 hrs for M to catch S
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the actual dist each traveled, should be the same.
\n" ); document.write( "15(4) = 60 mi
\n" ); document.write( "12(4+1) = 60 mi
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