document.write( "Question 715922: A chemist needs 120millileters of a 21% solution but has only 11% and 71% solutions avaible. Find how many millileters of each that should be mixed to get the desired solution. \n" ); document.write( "
Algebra.Com's Answer #439682 by josgarithmetic(39617)\"\" \"About 
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(target matter)/(amount of solution)=(target concentration)\r
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\n" ); document.write( "\n" ); document.write( "x = volume of 11%
\n" ); document.write( "y = volume of 71%\r
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\n" ); document.write( "\n" ); document.write( "\"%2811x%2B71y%29%2F120=21\" and \"x%2By=120\"\r
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\n" ); document.write( "\n" ); document.write( "Rational equation gives us
\n" ); document.write( "11x+71y=120*21
\n" ); document.write( "\"11x%2B71y=2520\"\r
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\n" ); document.write( "\n" ); document.write( "Solve the system for x and y:
\n" ); document.write( "\"11x%2B71y=2520\"
\n" ); document.write( "\"x%2By=120\"\r
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\n" ); document.write( "\n" ); document.write( "Multiplying the simple \"120\" equation by 11, then we have \"11x%2B71y=2520\" and \"11x%2B11y=1320\". Subtract the second equation from the first and ... find a value for y. Then use the simpler x+y=120 equation to find the value for x.\r
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\n" ); document.write( "\n" ); document.write( "\"11x%2B71y-11x-11y=2520-1320\"
\n" ); document.write( "\"60y=1200\", 6y=120
\n" ); document.write( "\"highlight%28y=20%29\", ml. of the 71% solution...
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