document.write( "Question 715944: The ages od a group of 50 women are approximately normally disributed with a mean of 50 years and a standard deviation of 6 years. One woman is randomly selected from the group, and her age is observed. Find the probability that her age will fall between 56 and 61 years. I don't understand this and I am having trouble. \n" ); document.write( "
Algebra.Com's Answer #439679 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The ages od a group of 50 women are approximately normally disributed with a mean of 50 years and a standard deviation of 6 years. One woman is randomly selected from the group, and her age is observed. Find the probability that her age will fall between 56 and 61 years. \n" ); document.write( "---- \n" ); document.write( "z(56) = (56-50)/6 = 1 \n" ); document.write( "That means 56 is 1 standard deviation above the mean. \n" ); document.write( "------ \n" ); document.write( "z(61) = (61-50)/6 = 1.8333 \n" ); document.write( "That means 61 is 1.8333 standard deviations above the mean. \n" ); document.write( "---- \n" ); document.write( "Use your z-chart, calculator, or other technology to \n" ); document.write( "find the area above the interval [1,1.8333] and below \n" ); document.write( "the normal curve. \n" ); document.write( "----- \n" ); document.write( "normalcdf(1,1.8333) = 0.1253 \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================== \n" ); document.write( " |