document.write( "Question 715875: 6x-3 divided by 3 in absolute value greater or equal to 7 dont know how to tell which method to use the or method or other \n" ); document.write( "
Algebra.Com's Answer #439648 by Edwin McCravy(20065)\"\" \"About 
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document.write( "\"abs%28%286x+-+3%29%2F3%29\" ≧ 7\r\n" );
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document.write( "Simplify by factoring out 3 in the numerator:\r\n" );
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document.write( "\"abs%283%282x+-+1%29%2F3%29\" ≧ 7\r\n" );
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document.write( "Then cancel the 3's\r\n" );
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document.write( "\"abs%28cross%283%29%282x+-+1%29%2Fcross%283%29%29\" ≧ 7\r\n" );
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document.write( "|2x - 1| ≧ 7\r\n" );
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document.write( "There are four rules for removing absolute value bars in\r\n" );
document.write( "absolute value inequalities:\r\n" );
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document.write( "If A is positive:\r\n" );
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document.write( "1.  |EXPRESSION| < A becomes \r\n" );
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document.write( "-A < EXPRESSION < A\r\n" );
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document.write( "2.  |EXPRESSION| ≦ A becomes \r\n" );
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document.write( "-A ≦ EXPRESSION ≦ A\r\n" );
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document.write( "3.  |EXPRESSION| > A becomes\r\n" );
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document.write( "EXPRESSION < -A  OR EXPRESSION > A \r\n" );
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document.write( "4.  |EXPRESSION| ≧ A becomes\r\n" );
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document.write( "EXPRESSION ≦ -A  OR EXPRESSION ≧ A\r\n" );
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document.write( "        |2x - 1| ≧ 7\r\n" );
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document.write( "is rule 4 above where EXPRESSION = 2x - 1 and A = 7\r\n" );
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document.write( "    |2x - 1| ≧ 7 becomes\r\n" );
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document.write( "2x - 1 ≦ -7  OR  2x - 1 ≧ 7\r\n" );
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document.write( "Solve each for x:\r\n" );
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document.write( "    2x ≦ -6 OR  2x ≧ 8  \r\n" );
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document.write( "Divide through by 2\r\n" );
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document.write( "     x ≦ -3 OR  x ≧ 4\r\n" );
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document.write( "Draw the graph on a number line:\r\n" );
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document.write( "<=========●--------------------●===========>\r\n" );
document.write( "-6 -5 -4 -3 -2 -1  0  1  2  3  4  5  6  7  8 \r\n" );
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document.write( "Then the interval notation for this is an abbreviation \r\n" );
document.write( "for the above graph:\r\n" );
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document.write( "                   (-∞,-3] U [4,∞)\r\n" );
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document.write( "Edwin

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