document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=715877>Question 715877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Completing the square. This is so difficult. Can someone show me easy steps to understand this.\r<BR>\n" );
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document.write( "1.)4x^2+x+3=0<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439645 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439645\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Step 1:  Divide through by the lead coefficient.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ \frac{1}{4}x\ +\ \frac{3}{4}\ =\ 0\">\r<BR>\n" );
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document.write( "Step 2: Add the opposite of the constant term to both sides.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ \frac{1}{4}x\ =\ -\frac{3}{4}\">\r<BR>\n" );
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document.write( "Step 3: Divide the coefficient on the first degree term by 2, square the result, and then add that result to both sides of the equation.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ \frac{1}{4}x\ +\ \frac{1}{64}\ =\ -\frac{3}{4}\ +\ \frac{1}{64}\">\r<BR>\n" );
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document.write( "Step 4: The result of step 3 is a perfect square trinomial in the LHS.  Factor it.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \left(x\ +\ \frac{1}{8}\right)^2\ =\ -\frac{47}{64}\">\r<BR>\n" );
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document.write( "Step 5: Take the square root of both sides.  Remember to consider both positive and negative roots.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ \frac{1}{8}\ =\ \pm\frac{i\sqrt{47}}{8}\">\r<BR>\n" );
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document.write( "Step 6: Add the opposite of the constant term in the LHS to both sides:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x\ =\  \frac{-1\ \pm{i\sqrt{47}}}{8}\">\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "<font face=\"Math1\" size=\"+2\">Egw to Beta kai to Sigma</font><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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