document.write( "Question 715846: suppose we are given two functions, say r(x) and s(x).
\n" ); document.write( "a) Is it true the r(x) + s(x) = s(x)+r(x)? why or why not
\n" ); document.write( "b) is it true that r(x)-s(x)=s(x)-r(x)?why or why not
\n" ); document.write( "c) is it true that r(0)=0? why or why not \n" ); document.write( "

Algebra.Com's Answer #439629 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Presume real-valued functions and presume

and

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\n" ); document.write( "\n" ); document.write( "a) Yes. The sum of two functions at a value is the sum of the two values of the functions. The set of real numbers is commutative under addition.\r
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\n" ); document.write( "\n" ); document.write( "b) No. The difference of two functions at a value is the difference of the two values of the function. But the set of real numbers is NOT commutative under addition. Counterexample:

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\n" ); document.write( "\n" ); document.write( "c) No. r(0) is the value of the function at zero. If

, then

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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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