document.write( "Question 715844: in 2005, the precent of U.S. drivers wearing seat belts was 82%. The number of drivers wearing seat belts in 2000 was 71%. Let y be the number of drivers wearing seat belts in the year x where x=0 represents the year 2000.
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document.write( "a) Write a linear equation that models the percent of US. drivers wearing seat belts in terms of the year x.
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document.write( "b) Use the equation found in part (a) to predict the number of U.S. drivers wearing seat belts in the year 2009. \n" );
document.write( "
Algebra.Com's Answer #439623 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! in 2005, the precent of U.S. drivers wearing seat belts was 82%. The number of drivers wearing seat belts in 2000 was 71%. Let y be the number of drivers wearing seat belts in the year x where x=0 represents the year 2000. \n" ); document.write( "---------- \n" ); document.write( "You have 2 points relating year and percent: \n" ); document.write( "(5,82) and (0,71) \n" ); document.write( "----------- \n" ); document.write( "a) Write a linear equation that models the percent of US. drivers wearing seat belts in terms of the year x. \n" ); document.write( "slope = (82-71)/(5-0) = 11/5 = 2.2 \n" ); document.write( "---- \n" ); document.write( "intercept = f(0) = 71 \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "y = 2.2x + 71 \n" ); document.write( "==============================\r \n" ); document.write( "\n" ); document.write( "b) Use the equation found in part (a) to predict the number of U.S. drivers wearing seat belts in the year 2009. \n" ); document.write( "---- \n" ); document.write( "f(9) = 2.2*9+71 = 90.8% \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============================= \n" ); document.write( " \n" ); document.write( " |