document.write( "Question 63130This question is from textbook
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document.write( ": A small firm produces both AM and AM/FM car radios. The AM radios take 15 h to produce, and the AM/FM radios take 20 h. The number of production hours is limited to 300 h per week. The plant’s capacity is limited to a total of 18 radios per week, and existing orders require that at least 4 AM radios and at least 3 AM/FM radios be produced per week. Write a system of inequalities representing this situation. Then, draw a graph of the feasible region given these conditions, in which x is the number of AM radios and y the number of AM/FM radios. \n" );
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Algebra.Com's Answer #43962 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1st: x+y<=18 \n" ); document.write( "2nd: 15x+20y<=300 \n" ); document.write( "4<=x<=15 \n" ); document.write( "2<=y<=14 \n" ); document.write( "------------ \n" ); document.write( "Solve 1st and 2nd for y to get: \n" ); document.write( "3rd: y<=-x+18 \n" ); document.write( "4th: y<=(-3/4)x+15 \n" ); document.write( "----------- \n" ); document.write( "Graph: \n" ); document.write( "Draw vertical lines at x=4 and x=15 \n" ); document.write( "Draw horizontal lines at y=2 and y=14 \n" ); document.write( "Graph y<=-x+18 \n" ); document.write( "Graph y<=(-3/4)x+15 \n" ); document.write( "--------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |