document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=715830>Question 715830</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the Change of Base Formula to evaluate log[3] 48. Then convert log[3] 48 to a logarithm in base 5. Round to the nearest thousandth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439614 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the Change of Base Formula to evaluate log[3] 48. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%283%2C48%29+=+log%2848%29%2Flog%283%29 ALIGN=MIDDLE  ALT=\"log%283%2C48%29+=+log%2848%29%2Flog%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Then convert log[3] 48 to a logarithm in base 5.<BR>\n" );
document.write( "The log of what base 5?<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Round to the nearest thousandth.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%283%2C48%29+=+log%2848%29%2Flog%283%29 ALIGN=MIDDLE  ALT=\"log%283%2C48%29+=+log%2848%29%2Flog%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "=~ 3.524 </SPAN>\n" );
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