document.write( "Question 715739: a certain alloy contains 9% silver , another alloy is 14% silver. HOW MUCH OF EACH TYPE SHOULD BE COMBINED TO MAKE 10 KG OF AN ALLOY THAT CONTAINS 12% SILVER? \n" ); document.write( "
Algebra.Com's Answer #439564 by josgarithmetic(39617)\"\" \"About 
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Amount of Silver divided by amount of alloy equals 12%.\r
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\n" ); document.write( "\n" ); document.write( "x the 9% Silver. y the 14% Silver.\r
\n" ); document.write( "\n" ); document.write( "\"%289x%2B14y%29%2F10=12\" and \"x%2By=10\".\r
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\n" ); document.write( "\n" ); document.write( "Use the rational percent equation first.
\n" ); document.write( "9x+14y=120\r
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\n" ); document.write( "\n" ); document.write( "The system to solve is this:
\n" ); document.write( "\"highlight%289x%2B14y=120%29\"
\n" ); document.write( "\"highlight%28x%2By=10%29\"\r
\n" ); document.write( "\n" ); document.write( "Try elimination. Multiply second equation by 9 and subtract from first equation. Solve for value of y.
\n" ); document.write( "9x+14y-9x-9y=120-90
\n" ); document.write( "5y=30
\n" ); document.write( "\"highlight%28y=6%29\" kg of the 14% alloy\r
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\n" ); document.write( "\n" ); document.write( "Use the second equation, the mass equation, to get the value for x.
\n" ); document.write( "\"highlight%28x=4%29\" kg of the 9% alloy
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