document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=715717>Question 715717</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor completely, then state the Greatest Common Factor.  I am totally lost, can you help me? \r<BR>\n" );
document.write( "\n" );
document.write( "x^2-9  \r<BR>\n" );
document.write( "\n" );
document.write( "x^2-6x + 9\r<BR>\n" );
document.write( "\n" );
document.write( "Thank you!\r<BR>\n" );
document.write( "\n" );
document.write( "I tried the first one, but I am not sure if I am correct.  Since there is no number that goes into both x^2 and 9, you have to use 1 as your GCF.  So I got 1(x^2-9) is that right, or am I totally off? \r<BR>\n" );
document.write( "\n" );
document.write( "The second one, again, didn't have a number in common, so I got 1(x^2-6x+9) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439557 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439557\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE x^2\ -\ 9\"> is the difference of two squares.  The difference of two squares factors to a conjugate pair of linear binomials, such as <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE a^2\ -\ b^2\ =\ (a\ +\ b)(a\ -\ b)\">\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE x^2\ -\ 6x\ +\ 9\"> is a perfect square trinomial.  You can tell because half of the first degree coefficient squared is equal to the constant term, as in <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE x^2\ -\ bx\ +\ \left(\frac{b}{2}\right)^2\ =\ \left(x\ -\ \frac{b}{2}\right)^2\">\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Once you have correctly factored each expression, the common factor should be obvious.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "<font face=\"Math1\" size=\"+2\">Egw to Beta kai to Sigma</font><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
document.write( "<div  DISABLED_style= \"text-align:center\"><a  rel=nofollow HREF=\"http://outcampaign.org/\" target=\"_blank\"><IMG STYLE=\"max-width:80%;\" src=\"http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png\" border=\"0\" alt=\"The Out Campaign: Scarlet Letter of Atheism\" width=\"143\" height=\"122\" /></a></div><BR>\n" );
document.write( "</font> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );