document.write( "Question 715564: If an investor invested $1300 in two mutual funds, one was at 5% and the other at 2%, and a total of $50 was the profit, how much was invested in each fund? \n" ); document.write( "
Algebra.Com's Answer #439505 by mananth(16946) You can put this solution on YOUR website! Part I 5.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 2.00% per annum ------------ Amount invested = y \n" ); document.write( " 1300 \n" ); document.write( "Interest----- 50 \n" ); document.write( " \n" ); document.write( "Part I 5.00% per annum ---x \n" ); document.write( "Part II 2.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 1300 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "5.00% x + 2.00% y= 50 \n" ); document.write( "Multiply by 100 \n" ); document.write( "5 x + 2 y= 5000.00 --------2 \n" ); document.write( "Multiply (1) by -5 \n" ); document.write( "we get \n" ); document.write( "-5 x -5 y= -6500.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -3 y= -1500 \n" ); document.write( "divide by -3 \n" ); document.write( " y = 500 \n" ); document.write( "Part I 5.00% $ 800 \n" ); document.write( "Part II 2.00% $ 500 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "800 --------- 5.00% ------- 40.00 \n" ); document.write( "500 ------------- 2.00% ------- 10.00 \n" ); document.write( "Total -------------------- 50.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |