document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=715600>Question 715600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If two opposite sides of a square are increased by 10 meters and the other sides are decreased by 5 meters, the area of the rectangle that is formed is 76 square meters. Find the area of the original square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439503 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439503\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the side of square be x\r<BR>\n" );
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document.write( "x+10<BR>\n" );
document.write( "and x-5 are the sides of the rectangle\r<BR>\n" );
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document.write( "(x+10)(x-5)= 76\r<BR>\n" );
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document.write( "x^2-5x+10x-50=76\r<BR>\n" );
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document.write( "x^2+5x-126=0\r<BR>\n" );
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document.write( "x^2+14x-9x-126=0\r<BR>\n" );
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document.write( "x(x+14)-9(x+14)=0\r<BR>\n" );
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document.write( "(x+14)(x-9)=0\r<BR>\n" );
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document.write( "x=-14 OR 9\r<BR>\n" );
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document.write( "ignore negative \r<BR>\n" );
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document.write( "side of square is 9\r<BR>\n" );
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document.write( " </SPAN>\n" );
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