document.write( "Question 8013: Ok, just need these set up...
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document.write( "1. Maria has $1.05 in dimes and nickels. She has 6 more nickels than dimes. How many nickels does Maria have?\r
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document.write( "2. What is the equation for the sum of three times a number and five is fourteen? \n" );
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Algebra.Com's Answer #4395 by glabow(165)![]() ![]() ![]() You can put this solution on YOUR website! You just need these \"set up\" and not solved, right? \n" ); document.write( "You choose variables for the number of dimes and nickels. Let's use d and n. \n" ); document.write( "So since a d is worth 10 cents and an n is worth 5 cents, \n" ); document.write( "10d + 5n = 105 \n" ); document.write( "Also, n is 6 more than d. That is, if we knew how many n there were, we could find how many d there were by subtracting 6. So, \n" ); document.write( "n - 6 = d \n" ); document.write( "You put this value for d in the first equation and get \n" ); document.write( "10n - 60 + 5n = 105 \n" ); document.write( "Solve that and you know how many nickels there were. \n" ); document.write( "Then subtract 6 and you know how many dimes there were. \n" ); document.write( "I say \"were\" because by now Maria has spent them!\r \n" ); document.write( "\n" ); document.write( "Your second question just reads like algebra. Let n be the number. \n" ); document.write( "So, three times the number and then five more is fourteen. \n" ); document.write( "3x + 5 = 14 \n" ); document.write( " |