document.write( "Question 715521: A merchant mixed 12 lb of a cinnamon tea with 6 lb of spice tea. The 18 pound mixture cost $39. A second mixture included 16 lb of the cinnamon tea and 10 lb of the spice tea. The 26 pound mixture cost $57. Find the cost per pound of the cinnamon tea and of the spice tea.\r
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Algebra.Com's Answer #439493 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Price of the cinnamon tea $/# = c
\n" ); document.write( "Price of the spice tea, $/# = s\r
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\n" ); document.write( "\n" ); document.write( "Mixture Size 18 Pounds
\n" ); document.write( "Amount Cinn___________12#
\n" ); document.write( "Amount Spice__________6#
\n" ); document.write( "Mixture Cost__________39$
\n" ); document.write( "Equation for Cost_____12*c+6*s=39\r
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\n" ); document.write( "\n" ); document.write( "Mixture Size 26 Pounds
\n" ); document.write( "Amount Cinn___________16#
\n" ); document.write( "Amount Spice__________10#
\n" ); document.write( "Mixture Cost__________57$
\n" ); document.write( "Equation for Cost_____16*c+10*s=57\r
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\n" ); document.write( "\n" ); document.write( "INITIALLY THE SYSTEM TO SOLVE:
\n" ); document.write( "\"12%2Ac%2B6%2As=39\"
\n" ); document.write( "\"16%2Ac%2B10%2As=57\"\r
\n" ); document.write( "\n" ); document.write( "The $39 equation can be simplified, dividing by 3.
\n" ); document.write( "The $39 equation is the same as \"4c%2B2s=13\".\r
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\n" ); document.write( "\n" ); document.write( "A BETTER SYSTEM:
\n" ); document.write( "\"highlight%284c%2B2s=13%29\"
\n" ); document.write( "\"highlight%2816c%2B10s=57%29\"\r
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\n" ); document.write( "\n" ); document.write( "The easiest next step is to multiply the \"13\" equation by 4 which will allow you to eliminate terms of x and solve for s, its value. I leave that advice and the rest of the solution for you to finish (or to comment on if you get stuck).\r
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