document.write( "Question 715558: There are 13 males and 18 females in the math class. If chosen completely at random, how many different ways can 3 males and 2 females be chosen to do problems on the board.
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Algebra.Com's Answer #439484 by DrBeeee(684)\"\" \"About 
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Use permutations.
\n" ); document.write( "To select 3 males from 13 is
\n" ); document.write( "(1) 13P3 = 13*12*11 = 1716
\n" ); document.write( "To select 2 females from 18 is
\n" ); document.write( "(2) 18P2 = 18*17 = 306
\n" ); document.write( "The total number of possible of 3 males AND 2 females is the product of (1) and (2) or
\n" ); document.write( "(3) total = 525096 groups
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