document.write( "Question 715553: an investor invest 2500 in two mutual funds, he invest 5% in one and 2% in the other, both funds totaled an earning of $95, how much did each fund earn? \n" ); document.write( "
Algebra.Com's Answer #439480 by mananth(16949) You can put this solution on YOUR website! Part I 5.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 2.00% per annum ------------ Amount invested = y \n" ); document.write( " 2500 \n" ); document.write( "Interest----- 95 \n" ); document.write( " \n" ); document.write( "Part I 5.00% per annum ---x \n" ); document.write( "Part II 2.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 2500 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "5.00% x + 2.00% y= 95 \n" ); document.write( "Multiply by 100 \n" ); document.write( "5 x + 2 y= 9500.00 --------2 \n" ); document.write( "Multiply (1) by -5 \n" ); document.write( "we get \n" ); document.write( "-5 x -5 y= -12500.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -3 y= -3000 \n" ); document.write( "divide by -3 \n" ); document.write( " y = 1000 \n" ); document.write( "Part I 5.00% $ 1500 \n" ); document.write( "Part II 2.00% $ 1000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "1500 --------- 5.00% ------- 75.00 \n" ); document.write( "1000 ------------- 2.00% ------- 20.00 \n" ); document.write( "Total -------------------- 95.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |