document.write( "Question 715480: In his motorboat, Bill travels upstream at top speed to his favorite fishing spot, a distance of 36 miles. It takes him 2 hours. Returning, he finds that the trip downstream, still at top speed, only takes 1.5 hours. Find the speed of Bill's boat and the speed of the current. \n" ); document.write( "
Algebra.Com's Answer #439479 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Boat speed speed =x mph \n" ); document.write( "current speed =y mph \n" ); document.write( "against current 2 hours \n" ); document.write( "with current 1.5 hours \n" ); document.write( " \n" ); document.write( "Distance with current 36 miles distance against current 36 \n" ); document.write( "t=d/r against current (x-y) \n" ); document.write( "36.00 / ( x - y )= 2.00 \n" ); document.write( " \n" ); document.write( "2.00 x - -2.00 y = 36.00 ....................1 \n" ); document.write( "with current (x+y) \n" ); document.write( "36.00 / ( x + y )= 1.50 \n" ); document.write( "1.50 ( x + y ) = 36.00 \n" ); document.write( "1.50 x + 1.50 y = 36.00 ...............2 \n" ); document.write( "Multiply (1) by 1.50 \n" ); document.write( "Multiply (2) by 2.00 \n" ); document.write( "we get 2.00 \n" ); document.write( "3.00 x + -3.00 y = 54.00 \n" ); document.write( "3.00 x + 3.00 y = 72.00 \n" ); document.write( "6.00 x = 126.00 \n" ); document.write( "/ 6.00 \n" ); document.write( "x = 21 mph \n" ); document.write( " \n" ); document.write( "plug value of x in (1) y \n" ); document.write( "2 x -2 y = 36 \n" ); document.write( "42 -2 -42 = 36 \n" ); document.write( "-2 y = 36 \n" ); document.write( "-2 y = -6 mph \n" ); document.write( " y = 3 \n" ); document.write( "Boat speed 21 mph \n" ); document.write( "current 3 mph \n" ); document.write( " \n" ); document.write( " |