document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63167>Question 63167</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find an equation of the circle centered at (6,-5) and passing through (1,7)<BR>\n" );
document.write( "thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43947 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43947\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find an equation of the circle centered at (6,-5) and passing through (1,7)<BR>\n" );
document.write( "thank you<BR>\n" );
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document.write( "If it passes thru (1,7) the length of the radius is:<BR>\n" );
document.write( "r=sqrt[(7--5)^2+(1-6)^2]=sqrt[144+25]=sqrt169=13<BR>\n" );
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document.write( "With the center at (6.-5) and radius = 13 the equation is:<BR>\n" );
document.write( "(x-6)^2 + (y+5)^2=13^2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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